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Physics

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Layla jogs with an average velocity of 2.4 m/s east. What is her displacement after 46 seconds?

Answer :

beicker beicker

Today at 9:23 AM

Answer:

[tex]{ \tt{displacement = velocity \times time }} \\ { \tt{ = 2.4 \times 46}} \\ { \tt{ = 110.4 \: m}}[/tex]

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