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in the 1991 world track and field championships in tokyo, mike powell jumped 8.95 m, breaking by a full 5 cm the 23-year long-jump record set by bob beamon. assume that powell’s speed on takeoff was 9.5 m/s (about equal to that of a sprinter) and that g 9.80 m/s2 in tokyo. how much less was powell’s range than the maximum possible range for a particle launched at the same speed?

Answer :

Mike Powell's range was 0.26 m less than the maximum possible range.

We know that,

Horizontal range of the projectile on a flat ground is,

R = v² sin 2θ / g

where,

R = Range

v = Velocity

θ = Angle of projection

g = Acceleration due to gravity

Given that,

v = 9.5 m / s

The maximum possible range of a projectile is achieved when the angle of projection is 45°

R = 9.5² sin 90° / 9.8

R = 9.21 m

The difference between maximum range and Mike Powell's range is

R = 9.21 - 8.95

R = 0.26 m

In a projectile motion, range is the horizontal distance between starting and ending point.

Therefore, Mike Powell's range was 0.26 m less than the maximum possible range.

To know more about range of a projectile

https://brainly.com/question/11315006

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