Answer :
The distance traveled is 10 km north.
The force is 2x10^4N and directed from the exact southeast. The vertical component of the force is
2x10^4 N sin 45 = 1.4 x 10^4 N
The work done is
1.4 x 10^4 N (10 x 10^3 m) = 1.41 x 10^8 N-m
The power done is
1.41 x 10^8 N-m (1 h) (3600 s/1hr) = 5.1 x 10^11 N-m/s or W
The force is 2x10^4N and directed from the exact southeast. The vertical component of the force is
2x10^4 N sin 45 = 1.4 x 10^4 N
The work done is
1.4 x 10^4 N (10 x 10^3 m) = 1.41 x 10^8 N-m
The power done is
1.41 x 10^8 N-m (1 h) (3600 s/1hr) = 5.1 x 10^11 N-m/s or W