At STP, how many moles are in 0.880L of He gas?

At STP the moles of helium gas present in 0.880L of vessel is 0.039 moles.
Moles of any gas will be calculated by using an ideal gas equation at STP as:
PV = nRT, where
P = pressure = 1 atm
V = volume = 0.880 L
n = moles of gas = ?
R = universal gas constant = 0.0820 L.atm / K.mol
T = absolute temperature = 273.15 K
On putting values we get,
n = (1)(0.880) / (0.082)(273.15)
n = 0.039 moles
Hence required moes of helium gas is 0.039 moles.
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