i have a question in Trig about tires spinning, angular speed, and revolutions per minute. Pic included

First of all, let's follow the suggestion given by the question and convert the speed of the truck from mi/h to in/min. We know that 1 mile is equivalent to 63360 inches and 1 hour is equivalent to 60 minutes. Then 55 mi/h is equivalent to:
[tex]55\text{ }\frac{mi}{h}=55\text{ }\frac{63360in}{60min}=55\cdot\frac{63360}{60}\frac{in}{min}=58080\frac{in}{min}[/tex]So we know that the truck travels 58080 inches in a minute. If we divide this distance by the circumference of the wheels we'll find the number of revolutions performed by them in a minute. The wheels have a 30 in diameter and since the circumference of a circle is given by the product between π and its diameter we have that the circumference of the wheels is:
[tex]\pi\cdot30in=30\pi in[/tex]Then the number of revolutions performed by each wheel in a minute is:
[tex]\frac{58080}{30\pi}=1936\pi[/tex]These are the rpm asked in the second question. This result can be used to solve the first part since we know that a revolution is performed when the wheels rotate 2π radians. This means that if we multiply the rpm by 2π we'll find the angular speed of the wheels in rad/min:
[tex]1936\pi\cdot2\pi=3872\pi^2[/tex]AnswerNow that we found the quantities requested we should express them as decimal numbers rounded to 1 decimal place.
The first answer is: 38215.1 rad/min
The second answer is 6082.1 rpm