CHALLENGE: Using Pythagorean Theoremto find the missing side of a shapeIn the diagram below of rhombus ABCD, thediagonals AC and BD intersect at E.BEHINT: DIAGONALS IN ARHOMBUS ARE PERPENDICULARBISECTORS OF EACH OTHERDсIf AC = 18 and BD = 24, what is the length of oneside of rhombus ABCD?

CHALLENGE: Using Pythagorean Theoremto find the missing side of a shapeIn the diagram below of rhombus ABCD, thediagonals AC and BD intersect at E.BEHINT: DIAGO class=

Answer :

We have that the equation for this is

So we have that the length of one side of the figure is

[tex]\begin{gathered} s=\frac{\sqrt[]{18^2+24^2}}{2}=\frac{\sqrt[]{324\text{ + 576}}}{2} \\ =\frac{\sqrt[]{900}}{2}=\frac{30}{2}=15 \end{gathered}[/tex]

So the answer is that one side of the figure have a length of 15.

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