Answer :
Let's start by calculating the probability of each event.
Event 1: Since spinner B has 9 red slices and 15 total slices, then the probability of landing in a red slice is:
[tex]P_1=\frac{9}{15}=\frac{3}{5}=0.6[/tex]Event 2: Since spinner A has only blue and red slices, it will always land on a blue or a red slice, so the probability is 100%, or 1:
[tex]P_2=1[/tex]Event 3: Spinne A has 5 blue slices and 10 total slices, so the probability of landing on a blue one is:
[tex]P_3=\frac{5}{10}=\frac{1}{2}=0.5[/tex]Event 4: Spinner B has 6 blue slices and 15 total slices, so the probability of landing in a blue slice is:
[tex]P_4=\frac{6}{15}=\frac{2}{5}=0.4[/tex]So, from least likely to most likely, we have:
Event 4, Event 3, Event 1, Event 2.