Answer :

You have the following function:

[tex]f(x)=x^3+2x^2-64x-128[/tex]

In order to graph the previous curve, calculate the values of the f(x) in an interval for x, for instance, in the interval (-2,1):

[tex]\begin{gathered} f(-2)=(-2)^3+2(-2)^2-64(-2)-128=0 \\ f(-1)=(-1)^3+2(-1)^2-64(-1)-128=-63 \\ f(0)=(0)^3+2(0)^2-64(0)-128=-128 \\ f(1)=(1)^3+2(1)^2-64(1)-128=-189 \end{gathered}[/tex]

The graph is shown below:

${teks-lihat-gambar} DexterR18698