Answer :

To find the x-intercepts of the function, set f(x)=0 and solve for x as shown below

[tex]\begin{gathered} f(x)=0 \\ \Rightarrow(x+4)^2(x-3)^3(x-2)=0 \\ \end{gathered}[/tex]

When x=-4, the first term is equal to zero; if x=3, the second term is zero, and when x=2, the third and final term is zero.

Therefore, the x-intercepts are at x=-4,3,2 (the roots of the function).

Thus, the answers are x=-4, x=3, and x=2 (points (-4,0), (3,0), and (2,0))

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