{-15}
1) Let's solve this expression:
[tex]\begin{gathered} \frac{x}{x+5}=\frac{3}{2}\text{ x2} \\ \frac{2x}{x+5}=3\text{ x(x+5)} \\ 2x=3(x+5) \\ 2x=3x+15 \\ 2x-3x=15 \\ -x=15 \\ x=-15 \end{gathered}[/tex]Note that we multiplied by 2 and then by (x+5) so that we could get rid of the denominators.
2) Examining the options, we can state that:
The solution set is S={-15}
Since there's one solution for that.