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3. To produce x units of a religious medal costs C(x) =12x + 29. The revenue is R(x) = 25x. Both C(x) and R(x) are in dollars.a. Find the break-even quantity (x value)b. Find the profit from 250 units.c. Find the number of units that must be produced for a profit of $130.

3. To produce x units of a religious medal costs C(x) =12x + 29. The revenue is R(x) = 25x. Both C(x) and R(x) are in dollars.a. Find the break-even quantity (x class=

Answer :

Part a.

The break-even point is where the cost equals to the revenue, that is,

[tex]C(x)=R(x)[/tex]

Then, by substituting the given information, we get

[tex]12x+29=25x[/tex]

So, by subtracting 12x to both sides, it yields,

[tex]\begin{gathered} 29=13x \\ or\text{ equivalently, } \\ 13x=29 \end{gathered}[/tex]

Then, x is given by

[tex]x=\frac{29}{13}=2.2307[/tex]

Then, by rounding to the nearest whole number, the break even quantity is 2 medals.

Part b.

The profit is equal to the revenue minus the cost, that is,

[tex]P(x)=R(x)-C(x)[/tex]

So we have

[tex]P(x)=25x-(12x+29)[/tex]

which gives

[tex]P(x)=13x-29[/tex]

By substituting x=25o into this result ,we have

[tex]\begin{gathered} P(250)=13(250)-29 \\ P(250)=3250-29 \\ P(250)=3221 \end{gathered}[/tex]

Therefore, the profit from 250 units is $3221.

Part c

In this case, we need to substitute P=130 into the profit function and find x, that is,

[tex]130=13x-29[/tex]

So, by adding 29 to both sides, we have

[tex]\begin{gathered} 159=13x \\ or\text{ equivalently, } \\ 13x=159 \end{gathered}[/tex]

Therefore, we have

[tex]\begin{gathered} x=\frac{159}{13} \\ x=12.23 \end{gathered}[/tex]

Therefore, by rounding to the nearest whole number, the number of medals to produce a profit of $130 is 12 medals.

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