Answer :

[tex]\begin{gathered} \frac{1}{2}(y-8)=\frac{1}{4}y-2 \\ \frac{y}{2}-\frac{8}{2}=\frac{1}{4}y-2 \\ collec\text{t like terms} \\ \frac{1}{2}y-\frac{1}{4}y=-2+4 \\ \frac{2y-y}{4}=2 \\ \text{cross multiply} \\ y=8 \end{gathered}[/tex]

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