[tex]\begin{gathered} (a)\text{ The parabola open downwards since we can observe that the parabola goes down} \\ \text{ as x increases.} \\ (b)\text{ the axis of symmetry is }x=-2 \\ (c)\text{ As observed in the graph, the intercepts are} \\ \text{x-intercept = }-3\text{ and }-1 \\ \text{y-intercept=}-3 \\ (d)\text{ As observed in the graph, to where the axis of symmetry lies,} \\ \text{ the vertex is at }(-2,1) \end{gathered}[/tex][tex]\begin{gathered} \text{ The }x-\text{coordinate of the vertex is the equation of the axis of symmetry of the parabola}. \\ \text{ For a quadratic function in the standard form }y=ax^2+bx+c, \\ \text{ The axis of symmetry is the vertical line} \\ x=-\frac{b}{2a} \end{gathered}[/tex]
