Answer :
The inscribed angle AEC is half of the sum of the intercepted arcs AC and DB.
[tex]34\degree=\frac{1}{2}(50\degree+DB)[/tex]To eliminate the denominator, multiply both sides of the equation by 2.
[tex]68\degree=50\degree+DB[/tex]To solve for arc DB, subtract both sides of the equation by 50.
[tex]18\degree=DB[/tex]Thus, the measure of arc DB is 18°.