Answer :
Let's call L the length of the rectangle and W the width of the rectangle
We know the length is 3 times its width:
L = 3W
The area of a rectangle is:
A=L*W
Substituting the condition above, we have:
A = (3W)*W
Operating:
[tex]A=3W^2[/tex]We know the area is 147 yd^2, so we equate:
[tex]3W^2=147[/tex]Solve for W:
[tex]W^2=\frac{147}{3}=49[/tex]Taking the square root on both sides:
[tex]W=\sqrt[]{49}=7[/tex]The width is 7 yd. Now we can easily find the length:
L=3W=3*7=21 yd
Finally, we calculate the perimeter of the rectangle. Recall the perimeter is calculated with the formula:
P=2L+2W
Thus, using the known values:
P=2*21+2*7=42 + 14 = 56 yd
The perimeter of the rectangle is 56 yd