Answer :
Part A:
Given data
[tex]\begin{gathered} 18.2\text{ m/462 ms} \\ =\frac{18.2\text{ m}}{462\text{ ms}} \\ =\frac{18.2\text{ m}}{462\text{ ms}}\times\frac{1\text{ ms}}{10^{-3}\text{ s}} \\ =39.393\text{ m/s} \end{gathered}[/tex]Thus, the above quantity in the SI unit is 39.393 m/s.
[tex]\begin{gathered} 9.81m/s^2\times2.5\text{ s} \\ =9.81\text{ }\frac{m}{s^2}\times2.5\text{ s} \\ =24.525\text{ m/s} \end{gathered}[/tex]Thus, the above magnitude in the SI unit is 24.525 m/s.