A car traveling at 13.6 meters per second crashes into a barrier and stops in 0.321 meters. How many times the weight of the child is this force? Answer must be in 3 significant digits.

Given data
*The given speed of the cacr is u = 13.6 m/s
*The given distance is s = 0.321 m
*The given mass of the child is m = 21.2 kg
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The weight of the child is calculated as
[tex]\begin{gathered} w=mg \\ =21.2\times9.8 \\ =207.76\text{ N} \end{gathered}[/tex]As the value of the force is calculated in part (b) is 6110 N
The ratio of the force to the weight of the child is calculated as
[tex]\begin{gathered} \frac{F}{w}=\frac{6110}{207.76} \\ F=29.40\times w \end{gathered}[/tex]