Answer :
First we need to find the slope
(-3, 13) and (0, 8)
[tex]\text{slope =}\frac{y_2-y_1}{x_2-x_1}[/tex]x₁ = -3 y₁=13 x₂=0 y₂=8
[tex]\text{slope =}\frac{8-13}{0+3}[/tex][tex]\text{slope =}\frac{-5}{3}[/tex]Next, find the intercept
x=0 y=8 and m = -5/3
substitute into y=mx+ b and solve for b
8 = -5/3(0) + b
b = 8
Substitute m =-5/3 and b = 8 into y=mx+ b
[tex]y\text{ = -}\frac{5}{3}x\text{ + 8}[/tex]The correct option is option 4)