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An object with a mass of 22.22 kg rests on a plane inclined 1.35° from horizontal. What is the coefficient of static friction on the incline?

Answer :

Given data

*The given mass of the object is m = 22.22 kg

*The angle above the horizontal is

[tex]\theta=1.35^0[/tex]

The formula for the coefficient of static friction on the incline is given as

[tex]\mu_s=\tan \theta[/tex]

Substitute the values in the above expression as

[tex]\begin{gathered} \mu_s=\tan (1.35^0) \\ =0.02 \end{gathered}[/tex]

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