A=50N left & B=200 N up
Explanation
to figure out this we need to assume the object is in repose, it means teh sum of all the forces equals zero ,
hence
Step 1
the sum of horizontal forces
a) vertical
[tex]\begin{gathered} B-200=0 \\ so,\text{ solve for B} \\ \text{add 200 in both sides} \\ B-200+200=0+200 \\ B=200 \\ so\text{ } \\ B=200\text{ N up} \end{gathered}[/tex]b)horizontal
[tex]\begin{gathered} 50-A=0 \\ \text{add A in both sides} \\ 50-A+A=A \\ 50=A \\ so,\text{ A is 50 N left} \end{gathered}[/tex]therefore, the answer is
A=50N left & B=200 N up
