Answer :

Problem

If x is a positive integer, is sqrt 1/x^2 greater than, less than, or equal to cube root of 1/x^3

Solution

For this case we can analyze the following:

If x is an integer then we can conclude that

x^3 >= x^2

So then we need to satisfy this relationship:

[tex]\frac{1}{x^2}>=\frac{1}{x^3}[/tex]

So then the solution for this case would be greater than or equal

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