Answer :
Answer:[tex]2.25\times10^{20}\text{ electrons}[/tex]Explanation:
Current, I = 3.0 A
Time, t = 12 s
The quantity of charge flowing through the battery is:
Q = It
Q = 3 x 12
Q = 36 coulombs
[tex]\begin{gathered} \text{Number of electrons in 1 coulomb of charge = 6}.24\text{ }\times10^{18}\text{ electrons} \\ \text{Number of electrons in 36 coulombs of charge = 6}.24\text{ }\times10^{18}\times36\text{ electrons} \\ \text{Number of electrons in 36 coulombs of charge = 2.25 }\times10^{20}\text{electrons} \end{gathered}[/tex]