Given:-
An circle with radius 12.
To find:-
[tex]\text{SRQ}[/tex]So now the formula to find the value is,
[tex]2\pi r\times\frac{\theta}{360}[/tex]Now we substitute the known values. we get,
[tex]2\pi r\times\frac{\theta}{360}=2\pi r\times\frac{75}{360}=5\pi[/tex]So the required answer is OPTION C.