To solve the problem for x by using the Pythagorean theorem, we will find a right triangle in the given problem to apply this theorem, as follows:
In the new figure above, we have a right triangle with two legs equal to 10 and 4, and a hypotenuse equal to x.
No, we apply the Pythagorean theorem to find x, as follows:
[tex]\begin{gathered} l_1²+l_2²=h² \\ \\ 4²+10²=x² \\ \\ x²=100+16 \\ \\ x=\sqrt{116} \\ \\ x=\sqrt{29\cdot2²} \\ \\ x=2\sqrt{29} \end{gathered}[/tex]
