Answer :

[tex]\begin{gathered} 9=18e^{-3k} \\ 0.5=e^{-3k} \\ ln(0.5)=-3k \\ k=-\frac{ln(0.5)}{3}=0.23105 \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} A=18e^{-0.23105\times8} \\ A=2.835 \end{gathered}[/tex]

Thus, the remaining amount is 2.835 g

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