Answer :

Answer:

137.18mL

Explanations:

To get the required volume, we will use the dilution formula expressed as:

[tex]C_1V_1=C_2V_2_{}[/tex]

C1 and C2 are the concentration of the solution

V1 and V2 are the corresponding volumes

Given the following parameters:

[tex]\begin{gathered} C_1=4.24M \\ C_2=0.705M \\ V_2=825mL \\ V_1=\text{?} \end{gathered}[/tex]

Substitute the given parameters into the formula:

[tex]\begin{gathered} V_1=\frac{C_2V_2}{C_1} \\ V_1=\frac{0.705\cancel{M}\times825mL}{4.24\cancel{M}} \\ V_1=\frac{581.625mL}{4.24} \\ V_1=137.18mL \end{gathered}[/tex]

Hence the required volume of KCL that must be diluted to make 825 milliliters of a 0.705 M KCl solution is 137.18mL

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