Answer :
Given equation of lines :
[tex]\begin{gathered} y=-\frac{2}{3}x-3 \\ y=\frac{3}{a}x-5 \end{gathered}[/tex]Since the lines are parallel
From the propertoes of parallel lines, the slope of parallel lines are always equal,
where in the general equation of line
[tex]\begin{gathered} y=m(x-a)+b \\ m\text{ is the slope} \end{gathered}[/tex]On comapring the the first equation of line with general equation of line
we get m=-2/3
so, slope of first line is -2/3
similarly on comparing second equation of line with the general equation of line,
we get m=3/a
so, slope of second line is 3/a
since slope of both the lines are equal because they are paralle,
[tex]\begin{gathered} \text{slope first line = slope of second line} \\ \frac{-2}{3}=\frac{3}{a} \\ \text{apply cross multiplication and then solve for a,} \\ -2a=3\times3 \\ -2a=9 \\ a=-\frac{9}{2} \end{gathered}[/tex]So, the value of a is -9/2
Answer : C. -9/2