Answer :

[tex]x\text{ = 1}[/tex]

Here, we want to find the value of x, given g(x)

What we have to do here is to substitute the value of g(x) into the equation

We have this as follows;

[tex]\begin{gathered} 12\text{ = 10x+2} \\ 12-2\text{ = 10x} \\ 10x\text{ = 10} \\ x\text{ = }\frac{10}{10} \\ x\text{ = 1} \end{gathered}[/tex]

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