Answer :
[tex]\begin{gathered} 5qt=6p+10c+2lb(m) \\ \text{where:} \\ p=\text{potatoes} \\ c=\text{carrots} \\ m=\text{meat} \end{gathered}[/tex][tex]2gal\times\frac{4qt}{1gal}=8qt[/tex]
Therefore:
[tex]\begin{gathered} \frac{8}{5}(5qt)=\frac{8}{5}(6p+10c+2lb(m)) \\ 8qt=2gal=9.6p+16c+3.2lb(m) \\ 2gal=10p+16c+4lb(m) \end{gathered}[/tex]It will need:
10 potatoes
16 carrots
4lb of stew meat