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Explanation:
[tex]\begin{gathered} \text{Given: log}_5(16)\text{ } \\ To\text{ convert to base e} \end{gathered}[/tex]
Applying change of base formula:
[tex]\begin{gathered} \log _ba\text{ = }\frac{\log_da}{\log_db}\text{ (For converting to base d)} \\ \\ \text{Applying same principle above to the log given:} \\ \log _516\text{ to base e:} \\ \log _516\text{ = }\frac{\log_e16}{\log_e5} \end{gathered}[/tex][tex]\begin{gathered} \text{The ratio of logarithm with base e:} \\ \text{ }\frac{\log_e16}{\log_e5} \end{gathered}[/tex]