Answer :
Given:
time of 1.85 seconds,
time of 1.10 seconds,
initial velocity = 0,
gravity acceleration = 9.8 m/s².
Unknown:
velocity V1 at t = 1.1 s (in m/s),
velocity V2 at t = 1.85 s (in mi/hr).
Equations:
[tex]V=V_0+a\cdot t[/tex]Setup:
(1 m/s is equal to 2.237 mi/hr)
[tex]\begin{gathered} a=g=9.8\text{ m/s}^2 \\ V_1=0+9.8\cdot1.1_{} \\ V_2=(0+9.8\cdot1.85)\cdot2.237 \end{gathered}[/tex]Solve:
[tex]\begin{gathered} V_1=9.8\cdot1.1 \\ V_1=10.78\text{ m/s} \\ \\ V_2=9.8\cdot1.85\cdot2.237 \\ V_2=40.56\text{ mi/hr} \end{gathered}[/tex]