Okay, here we have this:
Considering the provided triangle, we are going to calculate the side "x", so we obtain the following:
To find this measure we will use the law of sines, so we have:
[tex]\begin{gathered} \frac{c}{\sin(C)}=\frac{a}{\sin(A)} \\ c=\frac{a\cdot\sin(C)}{\sin(A)} \\ x=\frac{49*\sin(74)}{\sin(180-74-55)} \\ x=\frac{49*\sin(74)}{\sin(51)} \\ x\approx60.61\text{ in} \end{gathered}[/tex]Finally we obtain that the measure of x is approximately 60.61 in.