Answer :
It is required to find the equation of the line with a slope 3/5 and passes through (-10,-16)
The general equation of the line is y = mx + b
Where m is the slope and b is a constant
Given : the slope = m = 3/5
So, the equation will be:
[tex]y=\frac{3}{5}x+b[/tex]Find the value of b using the given point ( -10 , -16 )
[tex]\begin{gathered} -16=\frac{3}{5}\cdot-10+b \\ -16=-6+b \\ b=-16+6=-10 \end{gathered}[/tex]So, the equation of the line is:
[tex]y=\frac{3}{5}x-10[/tex]