Given:
To Find:
Missing side lengths
Explanation:
[tex]\begin{gathered} \cos \theta=\frac{Opposite\text{ side}}{\text{hypotenuse side}} \\ \cos 30\degree=\frac{AB}{BC} \\ \frac{\sqrt[]{3}}{2}=\frac{2\sqrt[]{3}}{BC} \\ BC=2\sqrt[]{3}\times\frac{2}{\sqrt[]{3}} \\ x=4 \end{gathered}[/tex][tex]\begin{gathered} \sin \theta=\frac{Opposite\text{ side}}{\text{hypotenuse side}} \\ \sin 30\degree=\frac{AC}{BC} \\ \frac{1}{2}=\frac{AC}{4} \\ AC=\frac{4}{2} \\ y=2 \end{gathered}[/tex]Final Answer:
[tex]\begin{gathered} x=4 \\ y=2 \end{gathered}[/tex]
