Answer:
We have the following chemical reaction:
[tex]N_2+3H_2\rightarrow2NH_3[/tex]First we calculate the moles of hydrogen that react. For this we use its molar mass:
[tex]M_{H_2}=2.1\frac{g}{mol}=2\frac{g}{mol}[/tex][tex]n_{H_2}=\frac{5.8g}{2\frac{g}{mol}}=2.9mol[/tex]Now, we know that for every 3 moles of H2 we need 1 mol of N2, so we calculate the moles of N2:
[tex]n_{N_2}=2.9mol_{H2}\frac{1mol_{N2}}{3mol_{H2}}=0.97mol[/tex]And now we use the nitrogen's molar mass to calculate the grams:
[tex]M_{N_2}=2.14\frac{g}{mol}=28\frac{g}{mol}[/tex][tex]m_{N2}=0.97mol.28\frac{g}{mol}=27g[/tex]So the answer is 27g