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Solve each system by substitution.y = x + 5 4x + y = 201. Substitute the value of from the first equation into the second equation. 4x + = 20 2. Now solve for .3. Substitute the value of in one of the original equations. Solve for .4. Write your answer as an ordered pair .Solution: ( , )

Solve each system by substitution.y = x + 5 4x + y = 201. Substitute the value of from the first equation into the second equation. 4x + = 20 2. Now solve for . class=

Answer :

[tex]\begin{gathered} \text{Given} \\ y=x+5 \\ 4x+y=20 \end{gathered}[/tex]

1. Substitute the value of y from the first equation to the second equation

4x + x+5 = 20 (First fill in the blank)

2. Solve for x

4x + x + 5 = 20

5x + 5 = 20

5x = 20 - 5

5x = 15

5x/5 = 15/5

x = 3

3. Substitute x = 3 to the original equation

y = x+5

y = 3 + 5

y = 8

4. Therefore, the solution of the system of equation is (3,8) (second fill in the blank)

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