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You have 3 6 sided dice. One is red one is blue one is green What is the probability that you roll a one on the red die a 2 on the blue die and a 3 on the green

Answer :

Solution

Step 1

[tex]Probability\text{ of any event = }\frac{number\text{ of required outcomes}}{number\text{ of sample space}}[/tex]

Step 2:

For each die, the number of sample space is (1 ,2,3,4,,6)

Note: AND represent multiplication

Step 3:

The probability that you roll a 1 on the red die a 2 on the blue die and a 3 on the green

[tex]\begin{gathered} =\text{ }\frac{1}{6}\text{ }\times\text{ }\frac{1}{6}\text{ }\times\text{ }\frac{1}{6} \\ \text{= }\frac{1}{216} \end{gathered}[/tex]

Final answer

[tex]\frac{1}{216}[/tex]

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