Answer :
[tex](\frac{11}{8}+\frac{1}{8})-\frac{5}{4}[/tex]
When you have an add or a substraction of two fractions with the same denominator you just do the operation as follow:
[tex](\frac{a}{b}\pm\frac{c}{b})=\frac{a\pm c}{b}[/tex]So, the first part (the add) will be:
[tex]\frac{11}{8}+\frac{1}{8}=\frac{11+1}{8}=\frac{12}{8}[/tex]Then, when you have an add or a substraction of two fractions with different denominator you do the operation as follow:
[tex](\frac{a}{b}\pm\frac{c}{d})=\frac{a\cdot d\pm c\cdot b}{b\cdot d}[/tex]So, the final operation will be:
[tex](\frac{12}{8}-\frac{5}{4})=\frac{(12\cdot4)-(5\cdot8)}{8\cdot4}=\frac{48-40}{32}=\frac{8}{32}[/tex]You can simplify and get the final answer:
[tex]\frac{8}{32}=\frac{4}{16}=\frac{2}{8}=\frac{1}{4}[/tex]Final answer 1/4