What is the fnet of the 1st fbd on the left

400
Explanation
Step 1
to know the net force, we need to add the forces ( vectors),so vertically we have
positive =1200 N
Negative = 800 N
so, the sum of vertical forces is
[tex]\begin{gathered} \sum ^{\square}_{y-\text{foces}}=1200N-800N \\ \sum ^{\square}_{y-\text{foces}}=400\text{ N} \end{gathered}[/tex]hence, the answer is 400 N
I hope this helps you
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