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Let B be between A and C. Use the Segment Addition Postulate to solve for s.Segment Addition Postulate: AB + BC = ACAB = 4s -18BC = 6s -12AC = 20a s = 6Ds = 18ONS = -12DIS= 5

Answer :

Given:

B be between A and C.

So,

[tex]AB+BC=AC[/tex]

if :

[tex]\begin{gathered} AB=4s-18 \\ BC=6s-12 \\ AC=20 \end{gathered}[/tex]

So, substite with the values of AB, BC and AC then solve for s

[tex](4s-18)+(6s-12)=20[/tex]

Combine like terms:

[tex]\begin{gathered} 4s+6s=20+18+12 \\ 10s=50 \end{gathered}[/tex]

Divide both sides by 10:

[tex]\begin{gathered} \frac{10s}{10}=\frac{50}{10} \\ \\ s=5 \end{gathered}[/tex]

So, the answer is :

[tex]s=5[/tex]

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