Answer :

Given: Two points (3,-7) and (-3,1).

Required: Graph the line that passes through the points (3,-7) and (-3,1) and determine the equation of the line.

Explanation:

Graph can easily be drawn, using the two given points (3,-7) and (-3,1).

Further, equation of line can be found using two point form. The line passing through two points (3,-7) and (-3,1) is

[tex]\begin{gathered} y-1=\frac{-7-1}{3-(-3)}(x-(-3)) \\ y-1=\frac{-8}{6}(x+3) \end{gathered}[/tex]

Solving further,

[tex]\begin{gathered} y-1=-\frac{4}{3}(x+3) \\ 3(y-1)=-4(x+3) \end{gathered}[/tex]

So

[tex]\begin{gathered} 3y-3=-4x-12 \\ 4x+3y+9=0 \end{gathered}[/tex]

Final Answer: The graph is drawn and equation of line passing through the points (3,-7) and (-3,1) is 4x+3y+9=0.

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