Answer :

For this case we have the following equation given:

[tex]4x-3y=12[/tex]

We can begin add 3y on both sides we got:

[tex]4x=12+3y[/tex]

And now we can divide both sides by 3 and subtracting 12 and we got:

[tex]\frac{4x-12}{3}=\frac{3y}{3}[/tex]

And we have this:

[tex]y=\frac{4x-12}{3}=\frac{4x}{3}-4[/tex]

And that would be the final answer.

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