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Brooke and Samuel had the same number of marbles. Brooke gave away 20 marbles and Samuel gave away 44 marbles. Brooke then had 3 times as many marbles as Samuel. How many marbles did Brooke and Samuel each have at first?

Answer :

Given:

Brooke and Samuel had same number of marbles.

Let x and y be the number of marbles Brooke and Samuel had.

At first, x=y ... (1)

(x-20)=3(y-44) .... (2)

Substitute equation (1) in (2,

[tex]y-20=3(y-44)[/tex][tex]y-20=3y-132[/tex][tex]3y-y=132-20[/tex][tex]2y=112[/tex][tex]y=56[/tex]

Therefore, Brooke and Samuel each have 56 marbles each at first.

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