Calculate the electric potential energy on the center of the square of the arrangement described as follows: Four charges are placed at the corners of a 11.36 cm square. The particles are as follows: 10.46 microC at x =0, y = 0, -11.34 microC at x = 11.36, y = 0, -16.6 microC at x = 11.36, y = 11.36, and 14.95 microC at x=0 and y = 11.36.

Answer :

Our arrange looks like the following:

The potential energy in each individual point is given by:

[tex]E_p=k\frac{Q}{d}[/tex]

As all points have the same distance from the center of the square, we can calculate a single distance. We'll need the pythagorean theorem in order to calculate the distance. It can be written as the following

[tex]c^2=a^2+b^2[/tex]

Then we can calculate this using half the side of the square. We get

[tex]c^2=5.68^2+5.68^2[/tex]

By isolating c we can find

[tex]c=\sqrt[2]{5.68^2+5.68^2}=8.03cm[/tex]

This is the distance from each vertex to the center

We also need to take into account the fact that the total potential energy is the sum of potential energies

[tex]E_p=E_A+E_B+E_C+E_D[/tex]

It can then be written as

[tex]E_p=k(\frac{q_1}{d}+\frac{q_2}{d}+\frac{q_3}{d}+\frac{q_4}{d})[/tex]

Which, once we plug our values in, yields:

[tex]E=(9*10^9)(\frac{(10.46-11.34-16.6+14.95)*10^{-6}}{8.03*10^{-2}})=-283561.6438J[/tex]

Thus, our final answer is 283561.6438J

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