highskye1
Answered

help!!!!!!
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5. Can any of the roots have multiplicity? How can you find a function that has these roots?

Answer :

wolf1728
I set up these three factors
(x-2) * (x-3) * (x-5) and then multiplied these to get this equation:

x^3 -10x^2 +31x -30 = 0

lublana

Answer:

The cubic polynomial function whose graph has zeroes at2,3,5  is given by

[tex]x^3-10x^2+31x-30[/tex].

No, any of the roots ave no multiplicity.

The function P(x)= [tex]x^3-10x^2+31x-30[/tex]

Step-by-step explanation:

Given  graph has zeroes at 2, 3and 5

 x=2

x-2=0

x=3

x-3=0

x=5

x-5=0

Multiply (x-2) , (x-3) and (x-5)

We get

[tex](x-2)\times (x-3)\times (x-5)[/tex]

after multiply we get an equation of cubic polynomial

= [tex]x^3-10x^2+31x-30[/tex]

Multiplicity : If a value of root repeated then the repeated value of root is called multiplicity.

Therefore , any root have no multiplicity because value of any root not repeated.

The function that has these roots is  given by

p(x)=[tex]x^3-10x^2+31x-30[/tex].

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