Answer :
Probability Theory
P (K) =[tex]\frac{n (K) }{n (S)}[/tex]
P(K) : probability of selected K
n (K) : number of occurence of K
n (S) : number of all occurence
In question is not contain information about the number of students who curry a gun, knife, or other weapon and the number of all students. so, we can desribe that :
n (A) : the number of occurence of students who curry a gun
n (B) : the number of occurence of students who curry a knife
n (C) : the number of occurence of students who curry other weapon
and the number of all students is n ( A U B U C) -> union of sets
how many randomly selected student? in question, there is no specific about the student. so, we can answer with :
1) probability of students who curry a gun
P (A) = [tex]\frac{n (A) }{n (AUBUC)}[/tex]
2) probability of students who curry a knife
P (B) = [tex]\frac{n (B) }{n (AUBUC)}[/tex]
3) probability of students who curry other weapon
P (C) = [tex]\frac{n (C) }{n (AUBUC)}[/tex]
and if question want to estimate with percentage, we can multiply with 100%. example :
1) percentage of probability of students who curry a gun
P (A) = [tex]\frac{n (A) }{n (AUBUC)}[/tex] x 100%
read more about probability at https://brainly.com/question/9772981
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