Answer :
The critical value that corresponds to a confidence interval of 95.9% is 1.99.
The distribution of the sample mean will be roughly normally distributed, according to the Central Limit Theorem, if we have an unknown population with a mean and standard deviation and adequately small random samples (n < 30) are chosen from the population with replacement.
Then, the mean of the sample means is given by,
μ(x) = μ
And the standard deviation of the sample means is given by,
σ = σ / [tex]\sqrt{n}[/tex]
In this case the sample selected is of size, n = 7.
As the sample size n = 7 < 30, the sampling distribution of sample mean will be approximately normal.
So, a z-interval will be used to estimate the population mean.
The confidence level is, 95.9%.
The value of α is:
∝ = 1 - confidence level
∝ = 1 - 0.959
∝ = 0.041
The critical value is:
[tex]z_{\frac{∝ }{2} }[/tex] = [tex]z_{\frac{0.041}{2} }[/tex]
[tex]z_{\frac{∝ }{2} }[/tex] = [tex]z_{0.0205}[/tex]
[tex]z_{\frac{∝ }{2} }[/tex] = -1.99
[tex]z_{1-∝/2}[/tex] = 1.99
Use a z-table.
Therefore,
The critical value that corresponds to a confidence interval of 95.9% is 1.99.
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