Answer :
624 nm x 10^-9 = 6.2 x 10^-7
(3.00 x 10^8) divided by (6.2 x 10^-7) = 4.8 x 10^14
(6.63 x 10^-34 J) x ( 4.8 x 10^14) = 3.2 x 10^-9 Joules
(3.00 x 10^8) divided by (6.2 x 10^-7) = 4.8 x 10^14
(6.63 x 10^-34 J) x ( 4.8 x 10^14) = 3.2 x 10^-9 Joules
Answer: The energy of the photon is [tex]3.185\times 10^{-19}J[/tex]
Explanation:
To calculate the energy of the photon, we use the equation given by Planck which is:
[tex]\Delta E=\frac{hc}{\lambda}[/tex]
where,
[tex]\lambda[/tex] = Wavelength of the photon = [tex]624nm=6.24\times 10^{-7}m[/tex] (Conversion factor: [tex]1m=10^9nm[/tex] )
h = Planck's constant = [tex]6.624\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\Delta E[/tex] = energy of the photon
Putting values in above equation, we get:
[tex]E=\frac{6.624\times 10^{-34}\times 3\times 10^8}{6.24\times 10^{-7}}\\\\E=3.185\times 10^{-19}J[/tex]
Hence, the energy of the complex is [tex]3.185\times 10^{-19}J[/tex]