Answer :
Omg that sounds sooo good anyway getting back on topic1) 5 chose 3 = 10
nCr = n! / (n - r)! r!
nCr = 5!/ (5 - 3)! 3!
nCr = 5!/ 2! 3!
nCr = (5 * 4 * 3 * 2 *1) / (2 * 1)(3 * 2 * 1)
nCr = 120 / (2 * 6)
nCr = 120 / 12
nCr = 10
2) 4 choose 2 (because 1 is always choc) = 6 by the formula above
3) 5^3 = 125
nCr = n! / (n - r)! r!
nCr = 5!/ (5 - 3)! 3!
nCr = 5!/ 2! 3!
nCr = (5 * 4 * 3 * 2 *1) / (2 * 1)(3 * 2 * 1)
nCr = 120 / (2 * 6)
nCr = 120 / 12
nCr = 10
2) 4 choose 2 (because 1 is always choc) = 6 by the formula above
3) 5^3 = 125