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An object is launched at 25 m/s from a height of 80 m. The equation for the height (h) in terms of time (t) is given by h(t)= -4.9t^2 + 25t + 80. What is the objects maximum height?

Answer :

Use the formula for finding axis of symmetry:


        -b           -25         -25         
x = ------  ⇒ --------- = -------- = 2.6 
       2a         2(-4.9)     -9.8



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